Given a force diagram with the values of the individual forces, determine the object mass, the net force, and the acceleration experienced by the object.
Consider the free-body diagram shown at the right. The values of the individual forces on a 2.82-kg object are:
Fgrav = Fnorm = 27.6 N
Fapp = 17.0 N
Ffrict = 6.5 N
Determine the net force acting upon the object. (Enter a - value if the direction is leftward.)
Net Force
N
Determine the horizontal acceleration of the object. (Enter a - value if the direction is leftward.)
Acceleration
m/s/s
Consider the free-body diagram shown at the right. The values of the individual forces on a 2.24-kg object are:
Fgrav = Fnorm = 22.0 N
Fthrust = 26.9 N
Ffrict = 11.6 N
Determine the net force acting upon the object whose force diagram is depicted at the right. (Enter a negative value if the direction is leftward.)
Consider the free-body diagram shown at the right. The values of the individual forces acting upon a 2.36-kg object are:
Fgrav = Fnorm = 23.1 N
Ftens = 32.2 N
Ffrict = 10.1 N
Consider the free-body diagram shown at the right. The values of the individual forces on a 2.94-kg object are:
Fgrav = Fnorm = 28.8 N
Fapp = 21.5 N
Ffrict = 5.4 N
Determine the net force (in Newtons) acting upon the object whose force diagram is depicted at the right. (Enter a negative value if the direction is leftward.)
Determine the horizontal acceleration (in m/s/s) of the object. (Enter a - value if the direction is leftward
The shipment of the new physics supplies have arrived. They are placed on the freight elevator and transported up to the third floor for delivery to the physics rooms. The free body diagram at the right depicts the forces acting upon the freight elevator as it begins its ascent through the elevator shaft. The values of the individual forces are:
Ftens = 3080.0 N
Fgrav = 2280.0 N
Fnorm1 = Fnorm2 = 240.0 N
Use the force values to determine the …
… net force on the elevator.
… the mass of the elevator.
Mass
kg
… the acceleration of the elevator.
Consider the free-body diagram shown at the right. The values of the individual forces are:
Fgrav = Fnorm = 26.8 N
Ftens = 38.8 N
Ffrict = 14.6 N
… net force on the object.
… the mass of the object.
… the acceleration of the object.
Fgrav = Fnorm = 229.0 N
Fapp = 182.0 N
Ffrict = 50.0 N
Consider the free-body diagram shown at the right. The object has a mass of 3.03-kg. There is a forward thrust force of 29.7 N. There is a backward friction force of 9.7 N. Determine the horizontal acceleration of the object. (Enter a - value if the direction is leftward.)
A 475.0-kg elevator is rising up an elevator shaft and approaching its destination. See diagram at right. The following force values are known:
Ftens = 3760.0 N
Fnorm1 = Fnorm2 = 65.0 N
Determine the vertical acceleration (in m/s/s) of the elevator. (Enter a - value if the direction is downward